Question

Find the torque about the origin when a force of
3j N acts on a particle whose position vector is
A
2 km​

Answer 1

Explanation:

Here r=

i

^

−

j

^

+

k

^

and F=7

i

^

+3

j

^

−5k.

We shall use the determinant rule to find the torque τ=r×F

τ=

∣

∣

∣

∣

∣

∣

∣

∣

i

^

1

7

j

^

−1

3

k

^

1

−5

∣

∣

∣

∣

∣

∣

∣

∣

=(5−3)

i

^

−(−5−7)

j

^

+(3−(−7))

k

^

or τ=2

i

^

+12

j

^

+10

k

^

Answer 2

Answer:

The torque is, τ=−6i^ Nm

Explanation:

The torque about any point is given as:

τ=r

×F

Substitute the value of force and radius vector:

τ=2k^×3j^​

τ=6(−i^)

τ=−6i^ Nm

What is torque?

The force that may cause an item to revolve along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.

A vector quantity is a torque. The force acting on the axis determines the direction of the torque vector. Torque is something that everyone who has ever opened a door can relate to. A door is opened by pushing on the side of the door that is furthest from the hinges. It takes a lot more pressure to push on the side closest to the hinges. Although both situations require the same amount of labour (the bigger force would be exerted over a shorter distance), individuals often prefer to use less force, which is why the door handle is typically located where it is.

To know more about torque , visit:

https://brainly.in/question/2199910

https://brainly.in/question/20039501

#SPJ3