Question

Find the torque acting on a rotating body, if it's angular momentum changes
from 5 kgm²/s to 8 kgm/s in 4 seconds.​

Answer 1

Answer:

• The Torque acting is 3/4 N-m

Explanation:

From the definition of torque we know that, Torque is defined as rate of change of angular momentum.

So, the relation between them is,

$\longrightarrow\sf \tau =\dfrac{\Delta L}{\Delta T}$

Solving,

$\longrightarrow\sf \tau=\dfrac{L_{f} - L_{i}}{T_{f}-T_{i}}\\\\\\\\\longrightarrow\sf \tau = \dfrac{8-5}{4-0}\\\\\\\\\longrightarrow\sf \tau = \dfrac{3}{4}\;Nm$

∴ The Torque acting on the body is 3/4 N-m.

Answer 2

Question given:

• Find the torque acting on a rotating body, if it's angular momentum changes from 5 kgm²/s to 8 kgm/s in 4 seconds

Information provided with us:

• Angular momentum of of a rotating body changes from 5 kgm²/s to 8 ms²/s
• Time taken is of 4 seconds

What we have to calculate:

• We have to calculate and find out the torque which was acting on that rotating body.

Using Formula:

• $\red \bigstar \: \underline{ \boxed{\bf{τ \: = \: \dfrac{ \triangle L}{ \triangle \: T } }}}$

Here,

• L is distance
• F is magnitude

It states that,

$\tt{τ \: = \: \dfrac{Distance(L) _{f} - distance(L) _{1} } {time _{f} - time _{1} } }$

Again where,

• f is magnitude
• L is distance

We have,

$\star \: \tt{L _{f} \: is \: 8}$

$\star \: \tt{L _{1} \: is \: 5}$

$\star \: \tt{T _{f} \: is \: 4}$

$\star \: \tt{T _{1} \: is \: 0}$

$\pink \bigstar \: \underline{ \underline{ \sf{Substituting \: the \: values \: we \: get:- }}}$

$: \longmapsto \: \tt{τ \: = \: \dfrac{8 - 5}{4-0} }$

On subtracting 8 with 5 we gets 3,

$: \longmapsto \: \red{\boxed{\tt{τ \: = \: \dfrac{3}{4} }}}$

$\underline{ \sf{ Hence, \: Torque \: acting \: on \: the \: rotating \: body \: is \: of \: \dfrac{3}{4}Nm}}$

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