Find the torque of a force 7i+3j-5k about the origin the force acts on a particle whose vector is i-j+k
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Answered by
236
h☆eya your answer is here☆☆
Torque is defined as:
T = r × F
where
r = position vector = (i - j + k) m
F = force vector = (7i + 3j - 5k) N
a₁ = 1
a₂ = -1
a₃ = 1
b₁ = 7
b₂ = 3
b₃ = -5
c₁ = a₂b₃ - a₃b₂ = (-1)(-5) - (1)(3) = 2
c₂ = a₃b₁ - a₁b₃ = (1)(7) - (1)(-5) = 12
c₃ = a₁b₂ - a₂b₁ = (1)(3) - (-1)(7) = 10
T = c₁i + c₂j + c₃k
T = (2i + 12j + 10k) Nm
Torque is defined as:
T = r × F
where
r = position vector = (i - j + k) m
F = force vector = (7i + 3j - 5k) N
a₁ = 1
a₂ = -1
a₃ = 1
b₁ = 7
b₂ = 3
b₃ = -5
c₁ = a₂b₃ - a₃b₂ = (-1)(-5) - (1)(3) = 2
c₂ = a₃b₁ - a₁b₃ = (1)(7) - (1)(-5) = 12
c₃ = a₁b₂ - a₂b₁ = (1)(3) - (-1)(7) = 10
T = c₁i + c₂j + c₃k
T = (2i + 12j + 10k) Nm
Answered by
55
f=7i+3j-5k
r=i-j+k
T=i(-3×1+5×1)+j(7×1+5×1)-k(-7×1-3×1)
T=2i+12j+10k
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