Find the torque of a force \vec{F} = -3\hat{i} + 2\hat{j} + \hat{k} F =−3 i ^ +2 j ^ + k ^ acting at the point \vec{r} = 8\hat{i} + 2\hat{j} + 3\hat{k} r =8 i ^ +2 j ^ +3 k ^ about origin
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Answer:
ANSWER
L
=m[
r
×
v
]
m=2kg
r
=2t
i
^
−3t
2
j
^
=4
i
^
−12
j
^
(At t = 2 sec)
v
=
dt
d
r
=2
i
^
−6t
j
^
=2
i
^
−12
j
^
r
×
v
=(4
i
^
−12
j
^
)×(2
i
^
−12
j
^
)
=−24
k
^
L
=m(
r
×
v
)
=−48
k
^
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