Math, asked by sivausmuru, 6 hours ago

Find the total amount and total interest after one year if the interest is compounded half-yearly. Principal = ₹4000=₹4000equals, ₹, 4000 Rate of interest = 10 \%=10%equals, 10, percent per annum

Answers

Answered by parthhuriwal
2

Answer:

Compound interest is 415.25 Rs.

Step-by-step explanation:

In the given question,

Principal Amount, P = 4000

Time for interest , t = 1 year

Rate of interest, r = 10% per annum compounded quarterly

Now, we know that in case of compounded quarterly.

The rate of interest is reduced to 1/4 times of initial and time increases by 4 times.

So,

New rate, R = 10/4 = 2.5 %

New Time, T = 1 x 4 = 4 years

So,

Compound Interest is given by,

CI=P(1+\frac{r}{100})^{t}-PCI=P(1+100r)t−P

So,

\begin{gathered}CI=4000(1+\frac{2.5}{100})^{4}-4000\\CI=4000(1.025)^{4}-4000\\CI=4415.25-4000\\CI=415.25 \ Rs.\end{gathered}CI=4000(1+1002.5)4−4000CI=4000(1.025)4−4000CI=4415.25−4000CI=415.25 Rs.

Therefore, the Compound interest is 415.25 Rs.

Answered by DipanSamaddar
4

Answer:

Compound interest is 415.25

In the given question,

Principal Amount, P = 4000

Time for interest , t = 1 year

Rate of interest, r = 10% per annum compounded quarterly

Now, we know that in case of compounded quarterly.

The rate of interest is reduced to 1/4 times of initial and time increases by 4 times.

So,

New rate, R = 10/4 = 2.5 %

New Time, T = 1 x 4 = 4 years

So,

Compound Interest is given by,

CI=P(1+\frac{r}{100})^{t}-PCI=P(1+

100

r

)

t

−P

So,

\begin{gathered}CI=4000(1+\frac{2.5}{100})^{4}-4000\\CI=4000(1.025)^{4}-4000\\CI=4415.25-4000\\CI=415.25 \ Rs.\end{gathered}

CI=4000(1+

100

2.5

)

4

−4000

CI=4000(1.025)

4

−4000

CI=4415.25−4000

CI=415.25 Rs.

Therefore, the Compound interest is 415.25 Rs.

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