Question

Find the total amount of lime required to treat 2 mld of water having a total hardness of 200 mg/l as caco3.

Answer 1

Answer:

calcium carbonate (CaCO3) equivalent

Alkalinity test results are usually reported as mg/L CaCO3 equivalents. To convert chloride to CaCO3 equivalents, multiply the concentration of chloride ions in mg/L by 1.41, and for sulfate, multiply by 1.04.

Explanation:

The source water has high calcium (204 mg/L as CaCO3), high magnesium carbonate hardness (84 mg/L as CaCO3) and since the total hardness is less than the carbonate and bicarbonate alkalinity, then the total hardness is equivalent to the carbonate hardness and the noncarbonated hardness is zero.

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