Question

Find the total amount of nitrogen by mass that is found in 200 g Ammonium Nitrite​

Answer 1

Explanation:

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$H2SO4\implies\\1*2+32+16*4\:\:\:\:\:\:\:(multiplying\:atomic\:mass*\:no.\:of\:atoms)\\\implies\mathrm2+32+64\\\implies\mathrm98grams\\32\:GRAMS\:OF\:SULPHUR\:IN\:98grams\:OF\:H2SO4\\\\THEN,\\grams\:OF \:SULPHUR\:IN\:49grams\:OF\:H2SO4\\\implies\mathrm49\:\times\frac{98}{32} \\\implies\mathrm16grams\\THEREFORE,\\16 grams\:OF \:SULPHUR\:IS\:PRESENT\:IN\:49grams\:OF\:H2SO4$

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