Question

Find the total area covered by a cylindrical road roller in 500 revolutions if the circumference of its circular base is 132 cm and its width is 1.4 m.​

Answer 1

Answer:

$\qquad\qquad\underline{\textsf{\textbf{ \color{magenta}{Solution\:completed} }}}$

Solution:-

Given :

Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m

In one revolution, the road roller will cover an area equal to its lateral surface area.

So, in one revolution the area of the road covered = 2πrh

= 2*22/7*0.42*1

Area of the road in one revolution = 2.64 sq m

Therefore, in 750 revolutions, the area of the road = 2.64*750

= 1980 sq m