Question

Find the total area of figure ABCDEF using the information shown in the figure.​

Answer 1

Answer:

904

Step-by-step explanation:

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Answer 2

• Given:- FA= 24m, FB = 30 m, FE= 26m, EB= 28m , EC = 32m

And the hight of ∆ECD= 6 m and the hight of ∆BEC = 16 m

• To find:- The total area of figure ABCDEF

• Solution:- The total area of figure ABCDEF= ∆FAB+∆FBE+∆BEC+∆ECD

In ∆FAB hight = AB

& as angleBAF = 90°

FA²=FA²+AB²

Or, AB²= 900-576= 324=18²

Or, AB= 18m

so the area of ∆FAB = 1/2 × FA× hight = 1/2 × 24 × 18 = 216 m²

Now, In ∆ FBE, the area is =√{s(s-a)(s-b)(s-c)} = √{42(42-26)(42-28)(42-30)}=336m²

[as S= (26+28+30)/2= 42 ]

& now in ∆BEC, the area is = 1/2 × EC×hight = 1/2× 32×16 = 256m²

& In ∆ECD,the area is = 1/2× EC × 6 = 1/2×32×6= 96m²

The total area of figure ABCDEF= ∆FAB+∆FBE+∆BEC+∆ECD = 216+336+256+96= 904m²