find the total area of shaded region in the figure the measures are given in cm
Answers
Area of square : S^2 (S square) of square BEFC
= 6*6 = 36cm^2
HOPE IT WILL HELP
Area of right angled triangle = 1/2 * BASE * HEIGHT
(BED and GCF)
For the base = DE^2=DB^2 + EB^2
= (5)^2= (3)^2 + EB^2
= 25 = 9 + EB^2
= -9+25 = EB^2
= 16 = EB^2
= EB = 4 cm
=>> 1/2 * base * height (OF TRIANGLE BED)
=>> 1/2 * 4cm * 3cm
=>> 6 cm^2
similarly with the another right angled triangle GCF = 6 cm^2
so area of the lower shaded region = 36 + 36
= 72 cm^2
hence proved.