Question

find the total area of the shape​

Answer 1

Answer:

58(99)-+8::47----

#43))((

Answer 2

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ang(AOD)=360°-(60°+45°+120°)=135°

Total area.....

$= \pi \: (3) {}^{2} \times \frac{120}{360} + \pi \: (3) {}^{2} \times \frac{135}{360} + \\ \: \: \: \: \pi \: (5) {}^{2} \times \frac{45}{360} + \pi \: (2) {}^{2} \times \frac{60}{360} \\ = 3\pi \: + \frac{27}{8} \pi \: + \frac{25\pi}{8} + \frac{2\pi}{3} \\ = \frac{(3 \times 24)\pi + (27 \times 3)\pi+ (25 \times 3)\pi \: + (2 \times 8)\pi}{24} \\ = \frac{244\pi}{24} \\ = \frac{61\pi}{6}$

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