Question

find the total charge carried by electron in 1 gram of water

Answer 1

is no carried because is sharing electron for 1 or receive the 7 electrons.
I hope is my correct answer

Answer 2

Let's see...
The molar mass of an H2O
H
2
O
molecule is 2×1+1×16=18
2
×
1
+
1
×
16
=
18
grams
The total number of electrons per H2O
H
2
O
molecule is 2×1+1×8=10
2
×
1
+
1
×
8
=
10
The number of moles of H2O
H
2
O
in 1 kg of water is 1000/18=55.555...
1000
/
18
=
55.555...
The number of molecules of H2O
H
2
O
in 1 kg of water is 55.555...×6.022×1023=3.3455...×1025
55.555...
×
6.022
×
10
23
=
3.3455...
×
10
25
Therefore, the number of electrons in 1 kg of water is3.3455...×1025×10=3.3455...×1026
3.3455...
×
10
25
×
10
=
3.3455...
×
10
26
Finally, the total charge of those electrons is 3.3455...×1026×−1.602176×10−19=−5.360169×107
3.3455...
×
10
26
×
−
1.602176
×
10
−
19
=
−
5.360169
×
10
7
Coulombs.
For those that don't know, the number 6.022×1023
6.022
×
10
23
is the Avogadro constant and the number −1.602176×10−19
−
1.602176
×
10
−
19
is the charge of one Electron in Coulombs.