find the total charge carried by electron in 1 gram of water
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first of all, find number of mole of water
molecular weight of water = 18 g/mol
so, number of mole of water = 1/18
so, number of molecules of water = mole of water × Avogadro's number
= 1/18 × 6.023 × 10²³
= 0.3346 × 10²³
= 3.346 × 10²²
number of electrons in one molecule of water = 2 × 1e of hydrogen + 8e of oxygen = 10e
so, number of electrons in 3.346 × 10²² molecules of water = 10 × 3.346 × 10²²
= 3.346 × 10²³
now, charge on one electron =- 1.6 × 10^-19C
so, charge on 3.346 × 10²³ electrons = - 3.346 × 10²³ × 1.6 × 10^-19 C
= 5.35 × 10⁴ C
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