Question

Find the total charge stored in the network of capacitors connected
between A and B as shown in figure.
​

Answer 1

Answer:

answer is 9micro farad

Answer 2

The total charge stored by the network of capacitor is 27 μC

Explanation:

Given :

The potential difference between point A and B = 3 V

From seeing the figure we can say that, 12 μF and 6 μF are in parallel both sides.

From the rule of equivalent capacitor,

Parallel capacitance add together.

$C_{1} = 12+6 = 18$ μF

$C_{2} = 12+6 = 18$ μF

For second case $C_{1}$ and $C_{2}$ are in series,

$C_{eq.} = \frac{18 \times 18}{18+18}$

$C_{eq.} = 9$ μF

Now,  $C_{eq.}= \frac{Q}{V}$

   $Q = 9 \times 3 = 27$ μC

Thus, the total charge stored by the network of capacitor is 27 μC