find the total current through 3ohm resistor using superposition theorem and verify with loop analysis
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Given :- Let the current How in 3Ω is i, and 6Ω is i
1
=1ampere
i 1 +i
2 =IV A −V
B =i
1×3Ω=i
2 ×6⇒1×3=i
2 ×6
2i = 2
1ampere
Hence I=i
1 +i 2=1+0.5=1.5ampere
Req=2+
3+6
3×6 =2+ 93×6
=4Ω
equivalent circuit
Refer image .2
From KVL
1req=v
v=1.5×4
=6volt
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