Question

Find the total distance covered by an athelete in five round of a rectangular park
that is 50m long and 37m width.​

Answer 1

Answer:

Length of rectangular park = 30 m

Breadth of rectangular park = 20 m

∴ Perimeter of park = 2(30 20) = 100 m

So, distance covered by the athlete in 15 rounds = 15×100=1500m

Answer 2

$\huge \underline{ \rm{Answer}}$

$\large \underline{ \underline{ \frak{ \color{peru}Given::}}}$

$\mapsto \sf{Length \: of \: rectangle=50m}$

$\mapsto \sf{Breadth\: of \: rectangle=37m}$

$\large \underline{ \underline{ \frak{ \color{cyan}To \: find::}}}$

$\leadsto \sf{Total \: distance \: covered \: by \: athelete \: in } \\ \sf{5 \: rounds \: around \: rectangular \: track. }$

$\large \underline{ \underline{ \frak{ \color{orange}Formula \: required::}}}$

$\dag \underline{ \blue{\fbox \green{Perimeter of rectangular track=2(length+breadth)}}}$

$\large \underline{ \underline{ \frak{ \color{plum}According \: to \: Question::}}}$

${ \dashrightarrow\sf{Perimeter \: of \: rectangular \: track=2(length+breadth)}}$

${ \dashrightarrow \sf{Perimeter \: of \: rectangular \: track=2(50m+37m)}}$

${ \dashrightarrow \sf{Perimeter \: of \: rectangular \: track=2 \times 87m}}$

${ \dashrightarrow \sf{Perimeter \: of \: rectangular \: track=174m}}$

$\bf \underline{Then, }$

${ \dashrightarrow \sf{Distance \: travel \: by \: athlete \: in \: 5 \: rounds=5×Perimeter}}$

${ \dashrightarrow \sf{Distance \: travel \: by \: athlete \: in \: 5 \: rounds=5×174m}}$

${ \dashrightarrow \sf{Distance \: travel \: by \: athlete \: in \: 5 \: rounds=870m}}$

$\bf \underline{Hence, }$

$\: \: \: \: \: \: \star \underline{\red{\boxed {\rm \green{Distance \: travel \: by \: athlete \: in \: 5 \: rounds=870m}}}}$