find the total energy of the body of 5g which is at the height of 10 m from the earth and falling down straightly witj the velocity of 20 m /sec (take acceleration due to gravity as 10 m/sec ²
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Kinetic energy at 10 m of height,
= 1/2 * m * v²
= 1/2 * 0.005 * 20²
= 1/2 * 0.005 * 400
= 1 Joule.
Velocity of body when it is about to touch the ground,
v² = u² + 2gh
v² = 20² + 2*10*10
v² = 400 + 200
v = √600
v = 10√6 m/s
Now,
Kinetic energy of body when it touches the ground,
= 1/2 * m * v²
= 1/2 * 0.005 * (10√6)²
= 1/2 * 0.005 * 600
= 1.5 Joules.
Plz Mark It As Brainliest Answer And Drop A ♥
= 1/2 * m * v²
= 1/2 * 0.005 * 20²
= 1/2 * 0.005 * 400
= 1 Joule.
Velocity of body when it is about to touch the ground,
v² = u² + 2gh
v² = 20² + 2*10*10
v² = 400 + 200
v = √600
v = 10√6 m/s
Now,
Kinetic energy of body when it touches the ground,
= 1/2 * m * v²
= 1/2 * 0.005 * (10√6)²
= 1/2 * 0.005 * 600
= 1.5 Joules.
Plz Mark It As Brainliest Answer And Drop A ♥
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