Question

find the total energy stored in the capacitors in the network shown below.​

Answer 1

Answer:

Dont  know  

Explanation:

Answer 2

Answer
The equivalent capacitance of C
1
​
and C
2
​
in series
C
′
=
C
1
​
+C
2
​

C
1
​
C
2
​

​
=
2+2
2×2
​
=1
u
​
F
C' is in parallel with C
3
​
, so equivalent capacitance of C
1
​
, C
2
​
and C
3
​
is
C'' = 1+1= 2
u
​
F
C'' is in series with C
4
​
; their equivalent capacitance
C'' =
C
4
​
+C
′′

C
4
​
C
′′

​
=
2+2
2×2
​
=1
u
​
F
This is in parallel with C
5
​
; so equivalent capacitance across AB is C
AB
​
=1 +1=2F
Energy stored V=
2
1
​
C
AB
​
V
2
=
2
1
​
×2×10
−6
×(6)
2
=36×10
−6
J

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