Math, asked by punsangita423, 3 months ago

find the total length of wall surrounding a rectangular garden of length 23m a breath 21m.also find the length of the wire required to surround the wall seven times ​

Answers

Answered by aayushsharma7956
2

Answer:

THE TOTAL LENGHT IS 88m

AFTER,

SURROUNDING IT 7 TIMES THE LENGHT BECOMES 616m

Step-by-step explanation:

PARAMETERS GIVEN,

LENGHT = 23m

BREADTH = 21m

SO,

PERIMETER OF THE WALL = 2(LENGHT + BREADTH)

                                             = 2(23+21m)

                                             = 2*44m

                                             = 88m

NOW,

TO SURROUND THE WALL 7 TIMES,

THE TOTAL PERIMETER IS,

88m*7

616m

I HOPE YOU UNDERSTOOD THE QUESTION

Answered by Anonymous
17

Given:-

  • Length of garden = 23 m
  • Breadth of garden = 21 m

To find:-

  • The total length of wall?
  • The length of wire required to surround the wall 7 times?

Solution:-

Firstly, find the total length of wall.

Using Formula:-

\star{\boxed{\sf{\orange{Perimeter~ of~ rectangle = 2(l + b)}}}}

\large{\tt{\longmapsto{2(l + b)}}}

\large{\tt{\longmapsto{2(23 + 21)}}}

\large{\tt{\longmapsto{2\times 44}}}

\large{\tt{\longmapsto{88~ m}}}

Hence, the total length of wall is 88m.

Let's find the length of wire required to surround the wall 7 times.

\large{\tt{\longmapsto{Total~ length~ of~ wall \times 7}}}

\large{\tt{\longmapsto{88 \times 7}}}

\large{\tt{\longmapsto{616~ m}}}

Hence, the length of wire is 616 m.

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