Question

Find the total no of 10 digits whose sum is 4.

Answer 1

Answer:

here's ur answer mate..........

its 220..

4=4+0(one 4 & 9 zeroes)=> 1

4=3+1(one 3,one 1 & 8 zeroes)=> 2*9!/8!=18

4=2+2(two 2's & 8 zeroes)=> 9

4=1+1+2(two 1's & one 2)=> 9!/7! + 9!/(7!*2!)=72+36=108

4=1+1+1+1(four 1's)=> 9!/(6!*3!)=84

total no. of 10 digits no. whose sum is 4 =1+18+9+108+84=220

ans 220

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Answer 2

Answer:

I hope this help you