Find the total number of electron present in 0.1418 of chlorine
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Correct Question: Find the total number of electron present in 0.1418 grams of chlorine.
Solution: Molar Mass of Chlorine = 35.5 × 2 (Due to it's diatomic form) = 71 g/mol
→ 1 mol of Chlorine weighs = 71 gram
→ 71 gram = weight of 6.022 × 10²³ Cl₂ molecules
1 chlorine molecule contains = 34 electrons
→ 71 gram = weight of 6.022 × 10²³ × 34 electrons
→ 1 gram contain = 6.022 × 34 × 10²³/71 electrons
→ 0.1418 gram = 6.022 × 34 × 10²³/71 × 0.1418
→ 0.41 × 10²³ or 4.1 × 10²² electrons
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