Question

Find the total number of H. S and 'O' atoms in the following:
(a) 196 g H2SO4
(b) 196 amu H2SO4
(c) 5 mole H2S2O3
(d) 3 molecules H2S206.​

Answer 1

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Answer 2

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      ......(1)

• For (a):  196 g of $H_2SO_4$

Given mass of sulfuric acid = 196 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of }H_2SO_4=\frac{196g}{98g/mol}=2mol$

In 1 mole of sulfuric acid, 2 moles of hydrogen atoms, 1 mole of sulfur atom and 4 moles of oxygen atoms are present.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of atoms.

So, 2 moles of sulfuric acid will contain = $2\times 2\times 6.022\times 10^{23}=24.088\times 10^{23}$ number of Hydrogen atoms, $1\times 2\times 6.022\times 10^{23}=12.044\times 10^{23}$ number of Sulfur atoms and $4\times 2\times 6.022\times 10^{23}=48.176\times 10^{23}$ number of Oxygen atoms.

• For (b):  196 amu of $H_2SO_4$

Given mass of sulfuric acid = 196 amu = 196 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of }H_2SO_4=\frac{196g}{98g/mol}=2mol$

In 1 mole of sulfuric acid, 2 moles of hydrogen atoms, 1 mole of sulfur atom and 4 moles of oxygen atoms are present.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of atoms.

So, 2 moles of sulfuric acid will contain = $2\times 2\times 6.022\times 10^{23}=24.088\times 10^{23}$ number of Hydrogen atoms, $1\times 2\times 6.022\times 10^{23}=12.044\times 10^{23}$ number of Sulfur atoms and $4\times 2\times 6.022\times 10^{23}=48.176\times 10^{23}$ number of Oxygen atoms.

• For (c):  5 mole of $H_2S_2O_3$

In 1 mole of $H_2S_2O_3$, 2 moles of hydrogen atoms, 2 moles of sulfur atom and 3 moles of oxygen atoms are present.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of atoms.

So, 5 moles of $H_2S_2O_3$ will contain = $2\times 5\times 6.022\times 10^{23}=6.022\times 10^{24}$ number of Hydrogen atoms, $2\times 2\times 6.022\times 10^{23}=24.088\times 10^{23}$ number of Sulfur atoms and $3\times 2\times 6.022\times 10^{23}=36.132\times 10^{23}$ number of Oxygen atoms.

• For (d): 3 molecules of $H_2S_2O_6$

In 1 molecule of $H_2S_2O_6$, 2 atoms of hydrogen, 2 atoms of sulfur and 6 atoms of oxygen are present.