Math, asked by Kedarpandit, 1 year ago

find the total number of selection of at least one red ball from 4 red and 3 Green balls if the ball of the same colour are different

Answers

Answered by amitnrw
12

120 ways of selection  of at least one red ball from 4 red and 3 Green balls if the ball of the same color are different

Step-by-step explanation:

if 1 Ball selected

if only 1 Red ball is selected then  ⁴C₁ = 4 Ways

if 2 balls selected

one Red  one Green is selected  then = ⁴C₁ * ³C₁ = 4 * 3 = 12 Ways

two reds are  selected  then = ⁴C₂ = 6 Ways

12 + 6 = 18 Ways

if 3  balls selected

one Red  Two Green is selected  then = ⁴C₁ * ³C₂ = 4 * 3 = 12 Ways

two reds one one green are  selected  then = ⁴C₂  * ³C₁ = 18 Ways

3 reds are  selected  then = ⁴C₃ = 4 Ways

12 + 18 + 4  = 34 Ways

if 4  balls selected

1 Red  3 Green is selected  then = ⁴C₁ * ³C₃ = 4  Ways

2 Reds 2 Green are  selected  then = ⁴C₂  * ³C₂ = 18 Ways

3 reds 1  Green are  selected  then = ⁴C₃ * ³C₁  = 4 * 3 = 12  Ways

4 reds are  selected  then = ⁴C₄ = 1 Ways

4 + 18 + 12 + 1  = 35 Ways

if 5  balls selected

2 Red  3 Green is selected  then = ⁴C₂ * ³C₃ =6  Ways

3 Reds 2 Green are  selected  then = ⁴C₃  * ³C₂ = 12 Ways

4 reds 1  Green are  selected  then = ⁴C₄ * ³C₁  = 3  Ways

6 + 12 + 3  = 21 Ways

if 6  balls selected

3 Red  3 Green is selected  then = ⁴C₃ * ³C₃ = 4  Ways

4 Reds 2 Green are  selected  then = ⁴C₄  * ³C₂ = 3 Ways

4 + 3  = 7 Ways

if 7  balls selected

4 Red  3 Green is selected  then = ⁴C₄ * ³C₃ = 1  Ways

Total ways = 4 + 18 + 34 + 35 + 21 + 7 +  1 = 120

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