find the total number of three digits number which are divisible by 9
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Answer:
100
Step-by-step explanation:
first three digit no. divisible by 9=108
last 3 digit no. divisible by 9=999
999=108+(n-1) 9
999-108=(n-1) 9
891/9=(n-1)
99=n-1
n=100
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