Question

find the total number of voids in 0.50 mol of a compound having hexagonal close packed structure.​

Answer 1

Answer:

So the answer is (18.066×10²³)/2 = 9.033×10²³

Explanation:

first of all 0.5 mole of a compound would contain number of atoms in it.

WKT if N are the No. of atoms then 3N are No. of voids(2N⇒tetrahedral, N⇒octahedral) thus 3×((6.022 × 10²³)÷2)

Hope it helps...