Find the total number of ways in which 4 persons can be seated in 6 seats.
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Method 1
The first man can be seated in 6 ways
The second man can be seated in 5 ways
The third man can be seated in 4 ways
The fourth man can be seated in 3 ways
Since ALL four have to be seated, we apply the Fundamental Principle of Counting for AND condition and multiply them together.
6 x 5 x 4 x 3 = 360 ways.
Method 2
4 men can occupy 6 seats in P(6,4) ways.
P(6,4) = 6!/2! = 6 x 5 x 4 x 3 = 360 ways
The first man can be seated in 6 ways
The second man can be seated in 5 ways
The third man can be seated in 4 ways
The fourth man can be seated in 3 ways
Since ALL four have to be seated, we apply the Fundamental Principle of Counting for AND condition and multiply them together.
6 x 5 x 4 x 3 = 360 ways.
Method 2
4 men can occupy 6 seats in P(6,4) ways.
P(6,4) = 6!/2! = 6 x 5 x 4 x 3 = 360 ways
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