find the total percentage of oxygen in magnesium nitrate crystal : Mg(NO3)2.6H2O.
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Answered by
1
8.3%
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Answered by
0
Answer:
Molecular mass of Mg(NO3)2.6H2O = 24 + (14+ 48) + 6(18) = 256g
Therefore, percentage of oxygen
48/256 *100 = 18.75%
Explanation:
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