Question

find the total percentage of oxygen in magnesium nitrate crystal : Mg(NO3)2.6H2O.

Answer 1

Molecular mass of Mg(NO3)2.6H2O = 24 + (14+ 48) + 6(18) = 256g

Therefore, percentage of oxygen
48/256 *100 = 18.75%

Answer 2

The value of percentage of Oxygen is 74.9%.

Step-by-step process

The given compound = Mg$(NO_{3})_{2}$.6$H_{2}O$

To find =the percentage of Oxygen molecules in magnesium nitrate crystal

Solution:

The molar mass of the compound = 24.31 + (14.01 +48)2 + 108

Molar mass= 24.31+ (62.01)2 +108

Molar mass= 24.31+ 124.02+108

=256.33 grams

Now, the molar mass of all the O present in the compound = 6O+6O

6×16+6×16

96+96

192 Grams

So, the percentage of oxygen in the given compound = molar mass of O ×100÷total molar mass

Putting the values:

192×100÷256.33

19200÷256.33

=74.9%

Result:

Thus, the percentage of Oxygen is 74.9%.

(#SPJ2)