Find the total positive charge of all the protons in 5gm of water
Answers
Answer:
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Number of moles in 5 gm of water is given as
n = \frac{5}{18} = 0.28 molesn=
18
5
=0.28moles
1 mole consist of Avagadro number of molecules of water
so total number of water molecules
N_w = 0.28 \times 6.02 \times 10^{23}N
w
=0.28×6.02×10
23
N_w = 1.67 \times 10^{23}N
w
=1.67×10
23
now we know that each water molecule will have 10 number of proton in it
so total number of protons in all the molecules is given as
N_p = 10(1.67 \times 10^{23}) = 1.67 \times 10^24N
p
=10(1.67×10
23
)=1.67×10
2
4
now we know that total charge is given as
Q = NeQ=Ne
so we will have
Q = (1.67 \times 10^{24})(1.6 \times 10^{-19})Q=(1.67×10
24
)(1.6×10
−19
)
Q = 2.68\times 10^5 CQ=2.68×10
5
C
so above is the charge due to all water molecules
To find the total positive charge of all the protons in 5 grams of water, we need to first determine the number of protons present in this amount of water.
- Water has a chemical formula of H2O, which means that each molecule of water contains two hydrogen atoms (each with one proton) and one oxygen atom (with eight protons).
- Thus, the total number of protons in a molecule of water is 10.
- Next, calculate the number of water molecules present in 5 grams of water.
- Since the molar mass of water is 18 g/mol, 5 grams of water contains 5/18 moles of water molecules.
- Using Avogadro's number (6.022 × 10^23), we can calculate that 5 grams of water contains approximately 1.68 × 10^23 water molecules.
Finally, to determine the total positive charge of all the protons in 5 grams of water, multiply the number of protons in each water molecule (10) by the total number of water molecules in 5 grams of water (1.68 × 10^23), which gives us a total positive charge of approximately 1.68 × 10^24 units.
Therefore, the total positive charge of all the protons in 5 grams of water is approximately 1.68 × 10^24 units.
To learn more about protons from the given link.
https://brainly.in/question/6495028
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