Physics, asked by vinay364, 8 months ago

find the total resistance ?​

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Answers

Answered by 7KaRaN7
1

Answer:

Based on the given figure, the answer is 8.22 ohm.

Refer the attachment for explanation

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Answered by viperisbackagain
0

Explanation:

this question is going to be interesting

so let 2ohm be R1 and other 2 ohm be R1 so 6ohm be R3 and then again 2ohm be R4 and 5ohm be R5 10 ohm be R6 15 ohm be R7 as well as 3ohm be R8

so as we can see R1 and R2 are connected in parallel

R12 =  \frac{r1 \times r2}{r1 + r2}  \\  \\ then  \: R12 =  \frac{2 \times 2}{2 + 2}  \\ R12 =  \frac{1}{4}  \\  \\ R12 = 1ohm \:

where R12 represent sum of resistor R1 And R2

then R3 and R4 are connected in parallel

so

R34 =  \frac{r3 \times r4}{r3 + r4}  \\  \\ R34 =  \frac{6 \times 2}{6 + 2}  \\  \\ R34 =  \frac{12}{8}   \\  \\ R34 =  \frac{3}{2}

Now R5 R6 and R7 are connected in parallel

so

 \frac{1}{R567}  \ =  \frac{1}{r5}  +   \frac{1}{r6}  +  \frac{1}{r7}  \\  \\   \frac{1}{ \:  R567 } = \frac{1}{5}  +   \frac{1}{10}  +  \frac{1}{15} \\  \\   \frac{1}{R567}  =   \frac{6 + 3 + 2}{30}  =  \frac{11}{30}  \\  \\ so \: R567 =  \frac{30}{11} ohm

therefore R567 R12 R34 and R3 are connected in series

so

Req =  \frac{30}{11}  +  \frac{3}{2}  + 1 + 3 \\  \\ Req =  \frac{30}{11}  +  \frac{3}{2}  + 4 \\  \\ Req =  \frac{30}{11}  +  \frac{3 + 8}{2}   \\  \\  Req =  \frac{30}{11}  +  \frac{11}{2}   \\  \\ Req =   \frac{60 + 22}{22}  \\  \\ Req =  \frac{72}{22}  \\  \\ Req = 3.27ohm \:

hope it helps

be brainly

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