find the total resistance between a and b
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Resistance in series R' = 6+4=10ohm
Let Total resistance br R
Then,1/R = (1/10) + (1/5)
=(5+10)/50
=15/50
=3/10
Therefore,
R = 10/3 = 3.3ohm
Answered by
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Answer:
6 ohm and 4 ohm are series combination
Requivalent =6+4=10 ohm
5 ohm and 10 ohm are in parallel combination
1/R=1/5+1/10=1/10+2/10
Requivelent = 10/3 ohm
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