Question

Find the total resistance in the circuit​

Answer 1

Let the resistance be R1,R2,R3...R6, where

R1=4, R2=1, R3=2, R4=3, R5=6, R6=7

○Calculating Rp(R2,R3,R4)

1/Rp = (6+3+2)/6

=> 1/Rp = 11/6

=> 1.83 ohm

Now R1, Rp And R5 are in series, thus Rs

Rs = 4+1.83+6 = 11.83

Now Rs and R7 are in parallel

So Rp(Rs,R7)= (11.83*7)/11.83+7

=> 82.81/18.83

=> 4.39 ohms

Thus total resistance is 4.39 ohms

Answer 2

Answer:

The answer to this question is = 4.21 ohm

Explanation:

Given:

R1 = 4 ohm

R2 = 1 ohm

R3 = 2 ohm

R4 = 3 ohm

R5 = 6 ohm

R6 = 7 ohm

The total resistance if R2,R3 and R4 connected in parallel =

1/R = 1/R2 + 1/R3 + 1/R4

1/R = 1/1 + 1/2 + 1/3

1/R = 11/6

R = 6/11 ohm. (1)

The total resistance of R1 , R2 , R3 ,R4 ,R5 =

We have already found the total resistance of R2 ,R3 ,R4 so substitute it in the above equation

We get

R = 4 + 6/11 + 6

R = 116/11 ohm. (2)

The Total resistance in the circuit =

1/R = 1/R(2) + 1/R6

1/R = 1/116/11 + 1/7

1/R = 11/116 + 1/7

1/R = (77 + 116)/812

1/R = 193/812

R = 812/193 ohm = 4.21 ohm

I HOPE IT WILL HELP YOU.