Find the total resistance in the given circuit
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Explanation:
HERE R2 AND R3 ARE IN SERIES THUS EFFECTIVE RESISTANCE BETWEEN R2 AND R3 = R2+R3= 8+4 = 12
HERE THE EFFECTIVE RESISTANCE OF R2 AND R3 ARE PARALLEL WITH THE R4 THUS THE EFFECTIVE RESISTANCE BETWEEN THEM =R4 ×(R2+R3) /( R4+R2+R3)
=( 12×12) /(12+12)
=6
HERE THE EFFECTIVE RESISTANCE BETWEEN R1 AND ABOVE MENTIONED EFFECTIVE RESISTANCE IS IN SERIES...
THUS THE EFFECTIVE RESISTANCE = R1+ 6
6+6=12
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