Find the total resistance of circuit shown
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Hello !!
To answer your question, I will put resolution steps until you get the correct answer.
First step R(1,2,3).
1/eqR = (1/R1)+(1/R2) +(1/R3)
1/eqR = (1/2)+(1/5) +(1/10)
1/eqR = [(5 + 2)/10]+(1/10)
1/eqR = (7/10)+(1/10)
1/eqR = [(70 + 10)/100]
1/eqR = 80/100
80eqR = 100
eqR = 100/80
eqR = 1.25 Ω
Second step R(4,5).
1/eqR = (1/R4)+(1/R5)
1/eqR = (1/6) + (1/4)
1/eqR = [(4 + 6)/24]
1/eqR = 10/24
10eqR = 24
eqR = 24/10
eqR = 2.4 Ω
Third step R(6).
R6 = 1/(135/100) = 0.740 Ω
Fourth step [R(1,2,3)+R(4,5)+R(6)].
1.25 + 2.4 + 0.740 = 4.39 Ω
Fifth and last step [the result].
(4.39 × 5)/(4.39 + 5) = 2.33 Ω approx.
Final result : 2.33 Ω approx.
I hope I have collaborated !
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