Physics, asked by neeti17, 1 year ago

Find the total resistance of circuit shown​

Attachments:

Answers

Answered by LeonardEuler
1

Hello !!

To answer your question, I will put resolution steps until you get the correct answer.

First step R(1,2,3).

1/eqR = (1/R1)+(1/R2) +(1/R3)

1/eqR = (1/2)+(1/5) +(1/10)

1/eqR = [(5 + 2)/10]+(1/10)

1/eqR = (7/10)+(1/10)

1/eqR = [(70 + 10)/100]

1/eqR = 80/100

80eqR = 100

eqR = 100/80

eqR = 1.25 Ω

Second step R(4,5).

1/eqR = (1/R4)+(1/R5)

1/eqR = (1/6) + (1/4)

1/eqR = [(4 + 6)/24]

1/eqR = 10/24

10eqR = 24

eqR = 24/10

eqR = 2.4 Ω

Third step R(6).

R6 = 1/(135/100) = 0.740 Ω

Fourth step [R(1,2,3)+R(4,5)+R(6)].

1.25 + 2.4 + 0.740 = 4.39 Ω

Fifth and last step [the result].

(4.39 × 5)/(4.39 + 5) = 2.33 Ω approx.

Final result : 2.33 Ω approx.

I hope I have collaborated !

Similar questions