Question

Find the total Resistance of the circuit and the current flowing through it.

Answer 1

r1=2ohm
r2=6ohm
r3=3ohm
r4=105ohm
v=6v
r1 and r2 is in parallel
so we use
1/R=1/r1+1/r2
=1/2+1/6
=2/3.....(1)
r4 and 1/R in parallel from answer(1)
=105+2/3
=317/3....(2)

r3 and is parallel to r1+r2and r4

so we use 1/R=1/

r3+(r4+1/R)(from answer...(2)
=1/3+317/3
=106ohm

R=106ohm

v=iR
I=v/R
=6/106
=0.056A

Answer 2

$Here \: is \: the \: answer \: of \: your \: question$

`$\textbf{We have to find R and I}$`

→ [Figure is in Attachment !!]

→ [Formula in series = r1 + r2 + rn]

→ [Formula in parallel = 1/r1 + 1/r2 + 1/rn]

= Let r1 = 105 ohm

r2 = 3 ohm

r3 = 6 ohm

r4 = 2 ohm

V = 6 volt

Now,

r3 and r4 are parallel to each other

So,

1 /R = 1/r3 + 1/r4

1/R = 1/6 + 1/2

= (3 + 1)/6 = 4/6

= 2/3 ........(A)

Now, (A) and r1 are in series.

So,

R2 = 2/3 + 105

= 317/3 ............(B)

From the figure 2

1/R3 = 317/3 + 1/3

= 318/3 = 106

Now, we have to find I

So, V = IR

I = V/R

I = 6/106

= 0.0566 A

`$\textbf{Answer = 0.056 A or 0.06 A}$`