Physics, asked by oftheworldbest35, 7 months ago

find the total resistance of the following circuit in which r1=3ohm r2= 3ohm r3= 4ohm r4= 2ohm

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Answers

Answered by amitkumar44481
4

AnsWer :

3 Ohm.

Concepts Required :

  • Series Combination - series combination define as When Current follow only one path in whole Circuit and not change there direction, it said to be Series Combination.
  • Rs - R1 + R2 + R3... Rn.

  • Parellel Combination - parellel Combination define as When Current follow two or more path in there Circuit and and change there direction, it said to be Parallel Combination.
  • Rp - 1/R1 + 1/R2 + 1/R3...1/Rn.

Formula :

# Series Connection.

 \tt \dagger \:  \:  \:  \:  \:  R_s = R_1 + R_2 + R_3 ... R_n

# Parellel Connection.

 \tt \dagger \:  \:  \:  \:  \:\dfrac{1}{ R_P}= \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} ...  \dfrac{1}{R_n}

Solution :

We have,

  • A Circuit in which R1 , R2 , R3 and R4 are connect through it.

Let,

  • Current be ( I )

A/Q,

  • R1 and R2 are Connected in Series Combination. ( Path - 1 )
  • And, R3 and R4 are also connected in Series Combination. ( path -2 )
  • And, When Current ( I ) flow in the circuit the Current divided/ follow into two different path ( path 1 & path 2 )

So,

Taking Path 1.

 \tt \dagger \:  \:  \:  \:  \:  R_s = R_1 + R_2 + R_3 ... R_n

Where as,

  • R1 = 3 ohm.
  • R2 = 3 ohm.
  • R3 = 4 ohm.
  • R4 = 2 ohm.

 \tt\longmapsto R_s = R_1 + R_2.

 \tt \longmapsto R_s = 3 + 3.

 \tt \longmapsto R_s = 6\Omega .

\rule{90}1

Taking Path 2.

 \tt \longmapsto R_s = R_3 + R_4.

 \tt \longmapsto R_s = 4 + 2.

 \tt \longmapsto R_s = 6\Omega .

\rule{90}1

Now,

  • Path 1 & 2 follow Parellel combination.

Let,

  • Rs1 = 6 ohm. ( Path 1 )
  • Rs2 = 6 ohm. ( Path 2 )

 \tt \dagger \:  \:  \:  \:  \:\dfrac{1}{ R_P}= \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} ...  \dfrac{1}{R_n}

 \tt \longmapsto \dfrac{1}{ R_P}=\dfrac{1}{ 6} + \dfrac{1}{ 6}

 \tt\longmapsto \dfrac{1}{ R_P}=\dfrac{1 + 1}{ 6}

 \tt\longmapsto \dfrac{1}{ R_P}=\dfrac{2 }{ 6}

 \tt\longmapsto \dfrac{1}{ R_P}=\dfrac{1}{3}

 \tt\longmapsto R_P =3\Omega .

Therefore, the total Equivalent Resistance is 3 ohm.

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