Physics, asked by anamikasnair, 8 months ago

find the total resistance,voltage drop across each resistors and power for each resistors.​

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Answers

Answered by ParamPatel
5

Answer:

Current Electricity

Explanation:

A ] Total Resistance

in series

R equivalent = R1 + R2 + R3 = 3 kΩ + 10 kΩ + 5 kΩ = 18 kΩ

B ] Current

Current ( I ) = voltage / Resistance

= 9 / 18 kΩ

= 0.5 × 10-³ A

I = 0.5 mA .

C ] Drop across each resistor

1 ) 3 kΩ

V1 = I × r

= 0.5 × 10-³ × 3 × 10³

= 1.5 Volt

2 ) 10 k Ω

V2 = I × r

= 0.5 × 10-³ × 10 × 10³

= 5 volt .

3 ) 5 k Ω

V3 = I × r

= 0.5 × 10-³ × 5 × 10³

= 2.5 volt.

» [ Now to confirm ; add all drop across resistor to get the voltage of connected battery ] «

★ Vnet = V 1 + V2 + V3 = 1.5 + 5 + 2.5 = 9 volt

D ] Power across each resistor

1 ) 3 k Ω

P1 = V1 × I = 1.5 × 0.5 × 10-³

= 0.75 × 10-³ watt or 750 μ watt

2 ) 10 k Ω

P2 = V2 × I = 5 × 0.5 × 10-³

= 2.5 × 10-³ watt

3 ) 5 k Ω

P3 = V3 × I = 2.5 × 0.5 × 10-³

= 1.25 × 10-³ watt

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Hope it helps you .

Answered by branhamdechea
0

Answer:

Explanation:

idek bru

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