find the total savings of a boy who saves rs (8x-4y) Rs(5x+3y)rs(5y-2x)and Rs(2y-x) in four consecutive months
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total savings=8x-4y + 5x+3y + 5y-2x + 2y-x,
total savings=(8x+5x-2x-x)+(-4y+3y+5y+2y),
total savings=10x+6y
total savings=(8x+5x-2x-x)+(-4y+3y+5y+2y),
total savings=10x+6y
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Answered by
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Here is your ANSWER
(8x-4y)+(5x+3y)+(5y-2x)+(2y-x)
First remove the brackets.
8x-4y+5x+3y+5y-2x+2y-x.
we have to group the terms which have same variables with signs.
8x+5x-2x-x-4y+3y+5y+2y
now plus or minus the terms.
HERE IS YOUR ANSWER:
10x+6y.
(8x-4y)+(5x+3y)+(5y-2x)+(2y-x)
First remove the brackets.
8x-4y+5x+3y+5y-2x+2y-x.
we have to group the terms which have same variables with signs.
8x+5x-2x-x-4y+3y+5y+2y
now plus or minus the terms.
HERE IS YOUR ANSWER:
10x+6y.
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