Question

find the total surfacce area of the cuboid , whose dimensions are as follows 24 cm ,18 cm ,16 cm

Answer 1

$tsa \: of \: cuboid=2(lb+bh+lh) \\ \\ = 2(24\times18+18\times16+24\times16)$

$= 2(432 + 288 + 384)$

$= (2 \times 1104) {cm}^{2}$

$= 2208 \: {cm}^{2}$

PLEASE MARK ME BRAINLIEST

Answer 2

2(lb+bh+hl) =2(24*18+18*16+16*24)=2(432+288+384)2(1104)=2208cm sq.