Question

Find the total surface area of a brick with dimensions 22cm x 10cm x 8cm.
( Take π =22]
7

Answer 1

Given

dimensions of brick is 22cm by 10cm by 8cm

To Find

We have to find the total surface area of brick

$\sf\huge {\underline{\underline{{Solution}}}}$

Since, brick is in the form of a cuboid so, therefore it must have length , breadth and height

Length of brick = 22cm

breadth of brick = 10cm

height of brick = 8cm

Total surface area of brick = 2(lb+bh+hl)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$= 2(22*10+10*8+8*22)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$= 2(220+80+176)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$= 2(476)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$= 952

∴Total surface area of brick is 952cm²

Extra information=>

• Curved surface area of cuboid = 2(l+b)*h
• Volume of cuboid= l*b*h