Question

Find the total surface area of a cube, whose volume is 3√3a3 cubic units.​

Answer 1

Answer:

Volume = edge^3

3√3 = edge^3

edge = √3 units

So

Total surface area = 6*edge^2

= 6*(√3)^2

= 6*3

= 18 sq.units

Step-by-step explanation:

pls mark me brainliest

Answer 2

 =Answer:

18 sq.units

Step-by-step explanation:

Given volume of cube = .$3\sqrt{3a } ^{2}$

Let edge of cube be p.

$p^{3}$=$3\sqrt{3a } ^{2}$=($\sqrt{3a}^{3}$)

edge of cube  [ p = $\sqrt{30}$]

∴  Total surface area of cube  

=6$(\sqrt{3a} )^{2}$=3 X 6$a^{2}$

Total surface area of cube

=$18a^{2}$