find the total surface area of a cubiod whose dimension are 18 m, 12 cm And 15 cm
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• Find the total surface area of a cubiod whose dimension are 18 cm, 12 cm and 15 cm.
- TSA of cuboid = 1332 cm².
Given:
- Length of cuboid (L) = 18 cm
- Breadth of cuboid (B) = 12 cm
- Height of cuboid (H) = 15 cm
To Find:
- TSA of cuboid.
TSA of cuboid = 2[LB + BH + HL]
TSA of cuboid = 2[18 × 12 + 12 × 15 + 15 × 18]
TSA of cuboid = 2[216 + 180 + 270]
TSA of cuboid = 2[666]
TSA of cuboid = 1332 cm²
Hence, Total surface area of cuboid = 1332 cm².
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QUESTION
find the total surface area of a cubiod whose dimension are 18 m, 12 cm And 15 cm
Answer:
- TSA of cuboid = 1332 cm².
Given:
- Length of cuboid (L) = 18 cm
- Breadth of cuboid (B) = 12 cm
- Heightof cuboid (H) = 15 cm
To Find:
TSA of cuboid.
SOLUTION:
⟹ TSA of cuboid = 2[LB + BH + HL]
⟹ TSA of cuboid = 2[18 × 12 + 12 × 15 + 15 × 18]
⟹ TSA of cuboid = 2[216 + 180 + 270]
⟹ TSA of cuboid = 2[666]
⟹ TSA of cuboid = 1332 cm²
Hence, Total surface area of cuboid = 1332 cm².
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