Question

find the total surface area of a cuboid with dimensions 10cm,6cm and 4cm​

Answer 1

$\bf \: \underline{ Given} :$ ↴

$\sf \implies Length = 10 \: cm$

$\sf \implies Breadth = 6 \: cm$

$\sf \implies Height = 8 \: cm$

$\bf \: \underline{To \: find} :$ ↴

$\sf \implies Total \: surface \: area \: of \: cuboid.$

$\bf \: \underline{Formula \: to \: be \: used},$

$\boxed{ \sf \: Total \: surface \: area \: of \: cuboid = \red{2(LB +BH + HL)}\: Sq.unit}$

$\sf \: Where,$

$\sf \bull \: \implies \:L = Length$

$\sf \bull \: \implies \:B = Breadth$

$\sf \bull \: \implies \:H = Height$

$\sf \: Therefore,$

$\sf \: \underline{Putting \: the \: values} \: :$ ↴

$\sf \implies \sf \: {2 \: (10 \times 6 +6 \times 8+ 8 \times 10)}$

$\sf \implies \sf \: {2 \: (60+48+ 80)}$

$\sf \implies \sf \: {2 \: (108+ 80 )}$

$\sf \implies \sf \: {2 \: (188)}$

$\sf \implies\sf { \: 2 \: \times 188}$

$\sf \implies \sf \: 376$

$\underline{ \boxed{\pink{ \sf \: Hence \: total \: surface \: area \: of \: cuboid = 376\: cm^{2}}}}$

$\underline{\sf Some \: more \: information \: about \: Cuboid} :$ ↴

$\sf \: 1. \: Volume \: of \: cuboid : (Length \times Breadth \times Height) \: \underline{ Cubic \: units}$

$\sf \: 2. \: Diagonal \: of \: Cuboid : \sqrt{(L^{2} + B^{2} + H^{2}) }\: units$

$\sf\:3. \: Perimeter \: of \: cuboid : 4 \: (length + breadth + height)\:Sq.units$

$\sf \: 4. \: Total \: surface \: area : 2(LB +BH + HL)\: Sq.units$

$\sf \: 5. \: Lateral \: Surface \: area : 2 \: height \: (length + breadth) \: Sq.units$

Answer 2

248cm^2 is the answer...

Formula- 2[lb+bh+lh]

good day!