Find the total surface area of a hollow cylinder open at both ends, if its length is 28 cm, external radius is 7 cm and thickness is 1 cm.
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Answer:
2369.71 cm^2
Step-by-step explanation:
R= 7 cm
r= 7-1
= 6 cm.
h= 28 cm
T.S.A= 2π(R+r)(h+R-r)
=2×22/7(7+6)(28+7-6)
= 44/7×13×29
= 16588/7
= 2369.71 cm^2
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