Find the total surface area of an isosceles trapezoidal prism with parallel edges of the base 6 cm and 12 cm, the legs of the base 5 cm each, the altitude of the base 4 cm and height of the prism 10 cm
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Step-by-step explanation:
Given: parallel edges of the base 6 cm and 12 cm, the legs of the base 5 cm each, the altitude of the base 4 cm, and length of the prism 10 cm.
The lateral surface area of the trapezoidal prism (LSA) = the sum of the areas of each rectangular surface around the base = (6+12+5+5)10 = 280 square cms.
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