Question

Find the total surface area of an open cylindrical container of radius 14cm and height 12 cm​

Answer 1

Step-by-step explanation:

•Wehave

Wehaver=10cm

Wehaver=10cmand,height(h)=14 cm

Wehaver=10cmand,height(h)=14 cmNow,

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2×

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 7

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 7

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10)

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 =

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 7

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 +

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 7

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 =

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 7

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360 =1193.2cm

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360 =1193.2cm 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360 =1193.2cm 2

Wehaver=10cmand,height(h)=14 cmNow,Totalsurfaceareaofcylindericalvessel=2πrh+πr 2 =2× 722 ×10×14+ 722 ×(10) 2 = 76160 + 72200 = 78360 =1193.2cm 2 Hence, this is the answer.