Question

Find the total surface area of cubical box in m2 ,if its side is of length 250cm.​

Answer 1

Step-by-step explanation:

(1) length =12 cm breadth =10 cm height =5 cm

TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]

TSA=2[120+50+60]=2×230

[TSA=460cm

2

]

(2) length =5 cm breadth =3.5 cm height =1.4 cm

TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]

TSA=2[17.5+4.90+7.0]=2[29.4]

[TSA=58.8cm

2

]

(3) length =2.5 cm breadth =2 m height =2.4 m

TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]

TSA=2[0.05+4.8+0.0600]=2[4.91]

(4) length =8 m breadth =5 m height =3.5 m

TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]

TSA=2[40+17.5+28.0]=2[85.5]

[TSA=171.0m

2

]

Answer 2

• The total surface area (T.S.A.) of a cubical box = 37.5 m².

Given :

• Side of a cubical box = 250 cm.

To Find :

• The total surface area of cubical box in m².

Solution :

We have to find the total surface area of a cubical box in m².

Given,

Side of a cubical box = 250 cm.

The given value is in cm so, we need to convert cm to m.

For converting,

Centimeter into meter.

We have to divide 100 by the given value.

So,

$\implies \dfrac{25 \cancel0}{10 \cancel0} \: m$

$\implies \dfrac{25}{10} \: m$

$\implies 2.5 \: m$

Hence, the side of a cubical box is 2.5 m.

Now, we have to find the total surface area of a cubical box.

Total surface area (T.S.A.) of a cubical box = 6 × Side²

Now we have,

• Side = 2.5 m.

Now, substitute the value of side in the formula of total surface area of a cubical box.

$\implies 6 \times {(2.5 \: m)}^{2}$

$\implies 6 \times 6 .25 \: {m}^{2}$

$\implies 37.50 \: {m}^{2}$

$\implies 37.5 \: {m}^{2}$

Hence,

The total surface area (T.S.A.) of a cubical box is 37.5 m².