Question

find the total surface area of cuboid if it l=9m, b=5m, h=50cm convert it into cm?​

Answer 1

Given:

A cubiod with

• Length = 9 m
• Breadth = 5 m
• Height = 50 cm = 0.5 m

What To Find:

We have to find the total surface area (TSA) of cubiod and convert it into cm.

Formula:

TSA of cubiod = 2(lb + bh + hl)

Solution:

Using the formula,

⇒ TSA = 2(lb + bh + hl)

Substitute the values,

⇒ TSA = 2(9 × 5 + 5 × 0.5 + 0.5 × 9)

Multiply the numbers,

⇒ TSA = 2(45 + 2.5 + 4.5)

Add the numbers,

⇒ TSA = 2(52)

Multiply 2 by 52,

⇒ TSA = 104 m²

Convert it into cm²,

⇒ 104 m² = 1040000 cm²

Or written as

⇒ 1040000 cm² = 104⁴ cm²

∴ Hence, the total surface area of cubiod is 104⁴ cm².

Answer 2

Correct Question-:

• Find the total surface area of cuboid if it length =9 m , Breadth = 5m, Height = 50 cm .

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ Total\: Surface\;Area\;of\; Cuboid\:=104m²\:or\:1040000cm²}}}}}$

EXPLANATION-:

• $\frak{Given \:\: -:} \begin{cases} \sf{ Length_{Cuboid} = 9m } & \\\\ \sf{Breadth_{Cuboid} = 5 m.\: }& \\\\\sf{ Height _{Cuboid} = 50cm \: 0.5m \: \: \: [ 1m = 100 cm]}\end{cases}$
• $\frak{To \:Find\: -:} \begin{cases} \sf{Total\: Surface\;Area\;of\; Cuboid\: .}\end{cases}$

Now ,

• $\underline{\boxed{\star{\sf{\blue{ Total\: Surface\;Area\;of\; Cuboid\:= 2 (Length × Breadth + Height × Length + Breadth × Height)}}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{ Length_{Cuboid} = 9m } & \\\\ \sf{Breadth_{Cuboid} = 5 m.\: }& \\\\\sf{ Height _{Cuboid} = 50cm \: 0.5m \: \: \: [ 1m = 100 cm]}\end{cases}$

Now ,

• $\implies{\sf{\large { T.S.A =\: 2( 9 × 5 + 0.5 × 9 + 5 × 0.5) }}}$

• $\implies{\sf{\large { T.S.A =\: 2( 45 + 9.5 + 4.5) }}}$

• $\implies{\sf{\large { T.S.A =\: 2( 52) }}}$

• $\implies{\sf{\large { T.S.A =\: 104m² }}}$

• $\implies{\sf{\large { T.S.A =\:Convert\:into\: cm²\: 104m²= 1040000cm²}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{ Total\: Surface\;Area\;of\; Cuboid\:=104m²\:or\:1040000cm²}}}}}$

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