Question

Find the total surface area of cuboid whose e dimensions are :
length = 48cm, breadth = 6 dm and height = 1m.
tell the answer
please​

Answer 1

Answer:

4.7524m² or 47524cm²

Step-by-step explanation:

given :-

Length (l) = 48cm = 48/100 = 0.48m

Breadth (b) = 6dm = 6/10 = 0.6m

height (h) = 1m

Let total surface area = A

A = (l + b + h)² or l² + b² + h² + 2(lb+bh+lh) (both are same)

A = (0.48 + 0.6 + 1)²

A = 2.18² = 4.7524m² or 47524cm²

Answer 2

${{\underline{\underline{{\textsf{\textbf{Answer : }}}}}}}$

➙ The total surface area of the cuboid is 2.736m²

${{\underline{\underline{{\textsf{\textbf{Explanation : }}}}}}}$

Given dimensions,

➡ l (length) = 48cm or, 0.48m

➡ b (breadth) = 6dm or, 0.6m

➡ h (height) = 1m

• Here, we need to find the total surface area of the cuboid by using the suitable formula.

〄 Total surface area of a cuboid :

➪ 2[ (l*b) + (b*h) + (l*h) ]

From the given values :

➔ 2[(0.48*0.6) + (0.6*1) + (0.48*1)]

➔ 2[0.288 + 0.6 + 0.48]

➔ 2[1.368]

➔ 2.736m² ans.

Note behind :

• Here, the dimensions of the cuboid are given in different units so we have to convert them in same units suitably. And from the given values using the formula of total surface area of a cuboid we solve them.