Question

find the total surface area of cuboid whose length,bradth,hieght are 12cm,9cm and 8cm respectively​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore T.S.A\:of\:Cuboid=552\:cm^{2}}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Length = 12 \: cm \\ \\ \implies Breadth = 9 \: cm \\ \\ \implies Height = 8 \: cm \\ \\ \underline \bold{To \: Find : } \\ \implies T.S.A \: of \: cuboid = ?$

• According to given question :

$\bold{Using \: formula \: of \: t.s.a \: of \: cuboid : } \\ \implies t.s.a \: of \: cuboid = 2(LB + BH + HL) \\ \\ \implies T.S.A = 2 \times (12 \times 9 + 9 \times 8 + 8 \times 12) \\ \\ \implies T.S.A = 2 \times (108 + 72 + 96) \\ \\ \implies T.S.A = 2 \times 276 \\ \\ \bold{\implies T.S.A= 552 \: cm^{2} } \\ \\ \bold{\therefore Total \: surface \: area \: of \: cuboid \: is \: 552 \: {cm}^{2} }$

Answer 2

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

Length (l) = 12 cm

Height (h) = 8 cm

Breadth (b) = 9 cm

We know that ,

$\large \fbox{\fbox{ \sf TSA \: of \: Cuboid = 2 ( lb + bh + hl )}}$

$\sf \to TSA = 2 \bigg((12 \times 9 )+( 8 \times 9 )+ (8 \times 12) \bigg) \\ \\ \sf \to TSA = 2(108 + 72 + 96) \\ \\ \sf \to TSA = 2(276) \\ \\ \sf \to TSA = 552 \: \: {cm}^{2}$

Therefore , the required value is 552 cm²